1/2x+1/4=1/6x+3

Solution for 1/2x+1/4=1/6x+3 equation:

1/2x+1/4=1/6x+3

We move all terms to the left:

1/2x+1/4-(1/6x+3)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 6x+3)!=0

x∈R


We get rid of parentheses

1/2x-1/6x-3+1/4=0

We calculate fractions


72x^2/192x^2+96x/192x^2+(-32x)/192x^2-3=0

We multiply all the terms by the denominator


72x^2+96x+(-32x)-3*192x^2=0

Wy multiply elements

72x^2-576x^2+96x+(-32x)=0

We get rid of parentheses

72x^2-576x^2+96x-32x=0

We add all the numbers together, and all the variables

-504x^2+64x=0

a = -504; b = 64; c = 0;
Δ = b2-4ac
Δ = 642-4·(-504)·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-64}{2*-504}=\frac{-128}{-1008}
=8/63
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+64}{2*-504}=\frac{0}{-1008}
=0
$