If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/2x+1/4=3/8x
We move all terms to the left:
1/2x+1/4-(3/8x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 8x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/2x-(+3/8x)+1/4=0
We get rid of parentheses
1/2x-3/8x+1/4=0
We calculate fractions
128x^2/256x^2+128x/256x^2+(-96x)/256x^2=0
We multiply all the terms by the denominator
128x^2+128x+(-96x)=0
We get rid of parentheses
128x^2+128x-96x=0
We add all the numbers together, and all the variables
128x^2+32x=0
a = 128; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·128·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*128}=\frac{-64}{256} =-1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*128}=\frac{0}{256} =0 $
| 3z2-384=138 | | 9x-17=17-8 | | 6x+6x=12x^2 | | 8y+4=45 | | 4b-b=36 | | -z+8=5z+9+1 | | -10+16=x | | -5/3x-4=4/4x-5 | | 19x+(-7)=-25+10x | | -8(10+b)-2b=-34+3b | | 4z+2=z+20 | | (5−8i)−(−6−11i)=0 | | 10x+13=3x-36 | | 5(2x)+3(2x)=6 | | 2-4x=5x-7 | | 56/y+5=`3 | | 5x=×+12 | | 0.72-0.16x=0.40 | | 4(2x+9)5x=-3 | | 14x-3-11×=12 | | 5.7x-4=0.5 | | 1.08(1.24)(9-x)=10 | | 25+3x=12 | | 2x+3-4x=4x-1-4x | | 45-6a=-3(9-7) | | 9i-10=6i | | x=×-10 | | 35x-20=15 | | (3x-2X)+x=240 | | 2x+3-4x=-1 | | 6x*10=15 | | 5/3-z=1/2 |