1/2x+1/4x=3/12

Solution for 1/2x+1/4x=3/12 equation:

1/2x+1/4x=3/12

We move all terms to the left:

1/2x+1/4x-(3/12)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

1/2x+1/4x-(+3/12)=0

We get rid of parentheses

1/2x+1/4x-3/12=0

We calculate fractions


(-96x^2)/96x^2+48x/96x^2+24x/96x^2=0

We multiply all the terms by the denominator


(-96x^2)+48x+24x=0

We add all the numbers together, and all the variables

(-96x^2)+72x=0

We get rid of parentheses

-96x^2+72x=0

a = -96; b = 72; c = 0;
Δ = b2-4ac
Δ = 722-4·(-96)·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72}{2*-96}=\frac{-144}{-192}
=3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72}{2*-96}=\frac{0}{-192}
=0
$