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1/2x+1/5=5/4(-7x+7)
We move all terms to the left:
1/2x+1/5-(5/4(-7x+7))=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4(-7x+7))!=0We calculate fractions
x∈R
(20x(-)/(40x^2(-)+(-(5*2x*5)/(40x^2(-)+32x^2/(40x^2(-)=0
We calculate terms in parentheses: +(20x(-)/(40x^2(-)+(-(5*2x*5)/(40x^2(-)+32x^2/(40x^2(-), so:
20x(-)/(40x^2(-)+(-(5*2x*5)/(40x^2(-)+32x^2/(40x^2(-
We can not solve this equation
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