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1/2x+1/5x+1/2=33/10
We move all terms to the left:
1/2x+1/5x+1/2-(33/10)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/2x+1/5x+1/2-(+33/10)=0
We get rid of parentheses
1/2x+1/5x+1/2-33/10=0
We calculate fractions
(-3300x^2)/400x^2+50x/400x^2+80x/400x^2+50x/400x^2=0
We multiply all the terms by the denominator
(-3300x^2)+50x+80x+50x=0
We add all the numbers together, and all the variables
(-3300x^2)+180x=0
We get rid of parentheses
-3300x^2+180x=0
a = -3300; b = 180; c = 0;
Δ = b2-4ac
Δ = 1802-4·(-3300)·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-180}{2*-3300}=\frac{-360}{-6600} =3/55 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+180}{2*-3300}=\frac{0}{-6600} =0 $
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