1/2x+1/5y=-11/10;1/2x+3y=9/2

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2x+y=8
x+3y=14

Solution for 1/2x+1/5y=-11/10;1/2x+3y=9/2 system of equations: 


  • /| (1/2)*x+(1/5)*y-(-11/10) = 0| (1/2)*x+3*y-(9/2) = 0
  • We try to solve the equation: (1/2)*x+(1/5)*y-(-11/10) = 0
  • 1/2*x+1/5*y+11/10 = 0 // - 1/2*x+11/10
  • 1/5*y = -(1/2*x+11/10) // : 1/5
  • y = (-(1/2*x+11/10))/1/5
  • y = -5*(1/2*x+11/10)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (1/2)*x-5*3*(1/2*x+11/10)-(9/2) = 0| y = -5*(1/2*x+11/10)
  • x/2-15*(1/2*x+11/10)-9/2 = 0
  • -7*x-33/2-9/2 = 0
  • -7*x-21 = 0
  • -7*x-21 = 0 // + 21
  • -7*x = 21 // : -7
  • x = 21/(-7)
  • x = -3
  • We insert the solution into one of the initial equations of our system of equations
  • For y = -5*(1/2*x+11/10): 
  • y = -5*(11/10-3*1/2)
  • y = -5*(11/10-3/2)
  • y = -5*(-2/5)
  • y = 2/5*5
  • y = 2
  • We get a system of equations:
  • /| y = 2| x = -3

 

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