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1/2x+123=x
We move all terms to the left:
1/2x+123-(x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-1x+1/2x+123=0
We multiply all the terms by the denominator
-1x*2x+123*2x+1=0
Wy multiply elements
-2x^2+246x+1=0
a = -2; b = 246; c = +1;
Δ = b2-4ac
Δ = 2462-4·(-2)·1
Δ = 60524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{60524}=\sqrt{4*15131}=\sqrt{4}*\sqrt{15131}=2\sqrt{15131}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(246)-2\sqrt{15131}}{2*-2}=\frac{-246-2\sqrt{15131}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(246)+2\sqrt{15131}}{2*-2}=\frac{-246+2\sqrt{15131}}{-4} $
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