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1/2x+12=-4x
We move all terms to the left:
1/2x+12-(-4x)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x+4x+12=0
We multiply all the terms by the denominator
4x*2x+12*2x+1=0
Wy multiply elements
8x^2+24x+1=0
a = 8; b = 24; c = +1;
Δ = b2-4ac
Δ = 242-4·8·1
Δ = 544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{544}=\sqrt{16*34}=\sqrt{16}*\sqrt{34}=4\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{34}}{2*8}=\frac{-24-4\sqrt{34}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{34}}{2*8}=\frac{-24+4\sqrt{34}}{16} $
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