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1/2x+15=x-30+2x-120
We move all terms to the left:
1/2x+15-(x-30+2x-120)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(3x-150)+15=0
We get rid of parentheses
1/2x-3x+150+15=0
We multiply all the terms by the denominator
-3x*2x+150*2x+15*2x+1=0
Wy multiply elements
-6x^2+300x+30x+1=0
We add all the numbers together, and all the variables
-6x^2+330x+1=0
a = -6; b = 330; c = +1;
Δ = b2-4ac
Δ = 3302-4·(-6)·1
Δ = 108924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{108924}=\sqrt{4*27231}=\sqrt{4}*\sqrt{27231}=2\sqrt{27231}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(330)-2\sqrt{27231}}{2*-6}=\frac{-330-2\sqrt{27231}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(330)+2\sqrt{27231}}{2*-6}=\frac{-330+2\sqrt{27231}}{-12} $
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