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1/2x+16=-0.6-3x
We move all terms to the left:
1/2x+16-(-0.6-3x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(-3x-0.6)+16=0
We get rid of parentheses
1/2x+3x+0.6+16=0
We multiply all the terms by the denominator
3x*2x+(0.6)*2x+16*2x+1=0
We multiply parentheses
3x*2x+1.2x+16*2x+1=0
Wy multiply elements
6x^2+1.2x+32x+1=0
We add all the numbers together, and all the variables
6x^2+33.2x+1=0
a = 6; b = 33.2; c = +1;
Δ = b2-4ac
Δ = 33.22-4·6·1
Δ = 1078.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33.2)-\sqrt{1078.24}}{2*6}=\frac{-33.2-\sqrt{1078.24}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33.2)+\sqrt{1078.24}}{2*6}=\frac{-33.2+\sqrt{1078.24}}{12} $
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