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1/2x+2/4x=13
We move all terms to the left:
1/2x+2/4x-(13)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x!=0We calculate fractions
x!=0/4
x!=0
x∈R
4x/8x^2+4x/8x^2-13=0
We multiply all the terms by the denominator
4x+4x-13*8x^2=0
We add all the numbers together, and all the variables
8x-13*8x^2=0
Wy multiply elements
-104x^2+8x=0
a = -104; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-104)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-104}=\frac{-16}{-208} =1/13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-104}=\frac{0}{-208} =0 $
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