1/2x+2=2/8x-1

Solution for 1/2x+2=2/8x-1 equation:

1/2x+2=2/8x-1

We move all terms to the left:

1/2x+2-(2/8x-1)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 8x-1)!=0

x∈R


We get rid of parentheses

1/2x-2/8x+1+2=0

We calculate fractions


8x/16x^2+(-4x)/16x^2+1+2=0

We add all the numbers together, and all the variables

8x/16x^2+(-4x)/16x^2+3=0

We multiply all the terms by the denominator


8x+(-4x)+3*16x^2=0

Wy multiply elements

48x^2+8x+(-4x)=0

We get rid of parentheses

48x^2+8x-4x=0

We add all the numbers together, and all the variables

48x^2+4x=0

a = 48; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·48·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*48}=\frac{-8}{96}
=-1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*48}=\frac{0}{96}
=0
$