1/2x+2x=40

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Solution for 1/2x+2x=40 equation:



1/2x+2x=40
We move all terms to the left:
1/2x+2x-(40)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We add all the numbers together, and all the variables
2x+1/2x-40=0
We multiply all the terms by the denominator
2x*2x-40*2x+1=0
Wy multiply elements
4x^2-80x+1=0
a = 4; b = -80; c = +1;
Δ = b2-4ac
Δ = -802-4·4·1
Δ = 6384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6384}=\sqrt{16*399}=\sqrt{16}*\sqrt{399}=4\sqrt{399}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-4\sqrt{399}}{2*4}=\frac{80-4\sqrt{399}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+4\sqrt{399}}{2*4}=\frac{80+4\sqrt{399}}{8} $

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