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1/2x+3/4=5/6x-2
We move all terms to the left:
1/2x+3/4-(5/6x-2)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 6x-2)!=0We get rid of parentheses
x∈R
1/2x-5/6x+2+3/4=0
We calculate fractions
216x^2/192x^2+96x/192x^2+(-160x)/192x^2+2=0
We multiply all the terms by the denominator
216x^2+96x+(-160x)+2*192x^2=0
Wy multiply elements
216x^2+384x^2+96x+(-160x)=0
We get rid of parentheses
216x^2+384x^2+96x-160x=0
We add all the numbers together, and all the variables
600x^2-64x=0
a = 600; b = -64; c = 0;
Δ = b2-4ac
Δ = -642-4·600·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-64}{2*600}=\frac{0}{1200} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+64}{2*600}=\frac{128}{1200} =8/75 $
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