1/2x+3=2/3x+1,x

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Solution for 1/2x+3=2/3x+1,x equation:



1/2x+3=2/3x+1.x
We move all terms to the left:
1/2x+3-(2/3x+1.x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x+1.x)!=0
x∈R
We add all the numbers together, and all the variables
1/2x-(+x+2/3x)+3=0
We get rid of parentheses
1/2x-x-2/3x+3=0
We calculate fractions
-x+3x/6x^2+(-4x)/6x^2+3=0
We add all the numbers together, and all the variables
-1x+3x/6x^2+(-4x)/6x^2+3=0
We multiply all the terms by the denominator
-1x*6x^2+3x+(-4x)+3*6x^2=0
We add all the numbers together, and all the variables
3x-1x*6x^2+(-4x)+3*6x^2=0
Wy multiply elements
-6x^3+18x^2+3x+(-4x)=0
We get rid of parentheses
-6x^3+18x^2+3x-4x=0
We do not support expression: x^3

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