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1/2x+4/3x=11/18
We move all terms to the left:
1/2x+4/3x-(11/18)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/2x+4/3x-(+11/18)=0
We get rid of parentheses
1/2x+4/3x-11/18=0
We calculate fractions
(-198x^2)/108x^2+54x/108x^2+144x/108x^2=0
We multiply all the terms by the denominator
(-198x^2)+54x+144x=0
We add all the numbers together, and all the variables
(-198x^2)+198x=0
We get rid of parentheses
-198x^2+198x=0
a = -198; b = 198; c = 0;
Δ = b2-4ac
Δ = 1982-4·(-198)·0
Δ = 39204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{39204}=198$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(198)-198}{2*-198}=\frac{-396}{-396} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(198)+198}{2*-198}=\frac{0}{-396} =0 $
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