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1/2x+40=220-x
We move all terms to the left:
1/2x+40-(220-x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(-1x+220)+40=0
We get rid of parentheses
1/2x+1x-220+40=0
We multiply all the terms by the denominator
1x*2x-220*2x+40*2x+1=0
Wy multiply elements
2x^2-440x+80x+1=0
We add all the numbers together, and all the variables
2x^2-360x+1=0
a = 2; b = -360; c = +1;
Δ = b2-4ac
Δ = -3602-4·2·1
Δ = 129592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{129592}=\sqrt{4*32398}=\sqrt{4}*\sqrt{32398}=2\sqrt{32398}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-360)-2\sqrt{32398}}{2*2}=\frac{360-2\sqrt{32398}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-360)+2\sqrt{32398}}{2*2}=\frac{360+2\sqrt{32398}}{4} $
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