1/2x+40=x

Solution for 1/2x+40=x equation:

1/2x+40=x

We move all terms to the left:

1/2x+40-(x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

-1x+1/2x+40=0

We multiply all the terms by the denominator


-1x*2x+40*2x+1=0

Wy multiply elements

-2x^2+80x+1=0

a = -2; b = 80; c = +1;
Δ = b2-4ac
Δ = 802-4·(-2)·1
Δ = 6408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6408}=\sqrt{36*178}=\sqrt{36}*\sqrt{178}=6\sqrt{178}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-6\sqrt{178}}{2*-2}=\frac{-80-6\sqrt{178}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+6\sqrt{178}}{2*-2}=\frac{-80+6\sqrt{178}}{-4}
$