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1/2x+4=2/6x-8
We move all terms to the left:
1/2x+4-(2/6x-8)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 6x-8)!=0We get rid of parentheses
x∈R
1/2x-2/6x+8+4=0
We calculate fractions
6x/12x^2+(-4x)/12x^2+8+4=0
We add all the numbers together, and all the variables
6x/12x^2+(-4x)/12x^2+12=0
We multiply all the terms by the denominator
6x+(-4x)+12*12x^2=0
Wy multiply elements
144x^2+6x+(-4x)=0
We get rid of parentheses
144x^2+6x-4x=0
We add all the numbers together, and all the variables
144x^2+2x=0
a = 144; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·144·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*144}=\frac{-4}{288} =-1/72 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*144}=\frac{0}{288} =0 $
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