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1/2x+5=-2x+5
We move all terms to the left:
1/2x+5-(-2x+5)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x+2x-5+5=0
We multiply all the terms by the denominator
2x*2x-5*2x+5*2x+1=0
Wy multiply elements
4x^2-10x+10x+1=0
We add all the numbers together, and all the variables
4x^2+1=0
a = 4; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·4·1
Δ = -16
Delta is less than zero, so there is no solution for the equation
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