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1/2x+5=2x-6
We move all terms to the left:
1/2x+5-(2x-6)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-2x+6+5=0
We multiply all the terms by the denominator
-2x*2x+6*2x+5*2x+1=0
Wy multiply elements
-4x^2+12x+10x+1=0
We add all the numbers together, and all the variables
-4x^2+22x+1=0
a = -4; b = 22; c = +1;
Δ = b2-4ac
Δ = 222-4·(-4)·1
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-10\sqrt{5}}{2*-4}=\frac{-22-10\sqrt{5}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+10\sqrt{5}}{2*-4}=\frac{-22+10\sqrt{5}}{-8} $
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