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1/2x+5=3.5x-7
We move all terms to the left:
1/2x+5-(3.5x-7)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-3.5x+7+5=0
We multiply all the terms by the denominator
-(3.5x)*2x+7*2x+5*2x+1=0
We add all the numbers together, and all the variables
-(+3.5x)*2x+7*2x+5*2x+1=0
We multiply parentheses
-6x^2+7*2x+5*2x+1=0
Wy multiply elements
-6x^2+14x+10x+1=0
We add all the numbers together, and all the variables
-6x^2+24x+1=0
a = -6; b = 24; c = +1;
Δ = b2-4ac
Δ = 242-4·(-6)·1
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-10\sqrt{6}}{2*-6}=\frac{-24-10\sqrt{6}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+10\sqrt{6}}{2*-6}=\frac{-24+10\sqrt{6}}{-12} $
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