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1/2x+5=5+2x
We move all terms to the left:
1/2x+5-(5+2x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(2x+5)+5=0
We get rid of parentheses
1/2x-2x-5+5=0
We multiply all the terms by the denominator
-2x*2x-5*2x+5*2x+1=0
Wy multiply elements
-4x^2-10x+10x+1=0
We add all the numbers together, and all the variables
-4x^2+1=0
a = -4; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-4)·1
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*-4}=\frac{-4}{-8} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*-4}=\frac{4}{-8} =-1/2 $
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