1/2x+5=x-3

Solution for 1/2x+5=x-3 equation:

1/2x+5=x-3

We move all terms to the left:

1/2x+5-(x-3)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We get rid of parentheses

1/2x-x+3+5=0

We multiply all the terms by the denominator


-x*2x+3*2x+5*2x+1=0

Wy multiply elements

-2x^2+6x+10x+1=0

We add all the numbers together, and all the variables

-2x^2+16x+1=0

a = -2; b = 16; c = +1;
Δ = b2-4ac
Δ = 162-4·(-2)·1
Δ = 264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{264}=\sqrt{4*66}=\sqrt{4}*\sqrt{66}=2\sqrt{66}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{66}}{2*-2}=\frac{-16-2\sqrt{66}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{66}}{2*-2}=\frac{-16+2\sqrt{66}}{-4}
$