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1/2x+6=-6x+19
We move all terms to the left:
1/2x+6-(-6x+19)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x+6x-19+6=0
We multiply all the terms by the denominator
6x*2x-19*2x+6*2x+1=0
Wy multiply elements
12x^2-38x+12x+1=0
We add all the numbers together, and all the variables
12x^2-26x+1=0
a = 12; b = -26; c = +1;
Δ = b2-4ac
Δ = -262-4·12·1
Δ = 628
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{628}=\sqrt{4*157}=\sqrt{4}*\sqrt{157}=2\sqrt{157}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{157}}{2*12}=\frac{26-2\sqrt{157}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{157}}{2*12}=\frac{26+2\sqrt{157}}{24} $
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