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1/2x+6=5/4x
We move all terms to the left:
1/2x+6-(5/4x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/2x-(+5/4x)+6=0
We get rid of parentheses
1/2x-5/4x+6=0
We calculate fractions
4x/8x^2+(-10x)/8x^2+6=0
We multiply all the terms by the denominator
4x+(-10x)+6*8x^2=0
Wy multiply elements
48x^2+4x+(-10x)=0
We get rid of parentheses
48x^2+4x-10x=0
We add all the numbers together, and all the variables
48x^2-6x=0
a = 48; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·48·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*48}=\frac{0}{96} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*48}=\frac{12}{96} =1/8 $
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