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1/2x+9x=-6
We move all terms to the left:
1/2x+9x-(-6)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
9x+1/2x+6=0
We multiply all the terms by the denominator
9x*2x+6*2x+1=0
Wy multiply elements
18x^2+12x+1=0
a = 18; b = 12; c = +1;
Δ = b2-4ac
Δ = 122-4·18·1
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-6\sqrt{2}}{2*18}=\frac{-12-6\sqrt{2}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+6\sqrt{2}}{2*18}=\frac{-12+6\sqrt{2}}{36} $
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