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1/2x+9=4/5x
We move all terms to the left:
1/2x+9-(4/5x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/2x-(+4/5x)+9=0
We get rid of parentheses
1/2x-4/5x+9=0
We calculate fractions
5x/10x^2+(-8x)/10x^2+9=0
We multiply all the terms by the denominator
5x+(-8x)+9*10x^2=0
Wy multiply elements
90x^2+5x+(-8x)=0
We get rid of parentheses
90x^2+5x-8x=0
We add all the numbers together, and all the variables
90x^2-3x=0
a = 90; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·90·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*90}=\frac{0}{180} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*90}=\frac{6}{180} =1/30 $
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