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1/2x+9x+2=1/2x+5
We move all terms to the left:
1/2x+9x+2-(1/2x+5)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2x+5)!=0We add all the numbers together, and all the variables
x∈R
9x+1/2x-(1/2x+5)+2=0
We get rid of parentheses
9x+1/2x-1/2x-5+2=0
We multiply all the terms by the denominator
9x*2x-5*2x+2*2x+1-1=0
We add all the numbers together, and all the variables
9x*2x-5*2x+2*2x=0
Wy multiply elements
18x^2-10x+4x=0
We add all the numbers together, and all the variables
18x^2-6x=0
a = 18; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·18·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*18}=\frac{0}{36} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*18}=\frac{12}{36} =1/3 $
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