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1/2x+x=-9
We move all terms to the left:
1/2x+x-(-9)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
x+1/2x+9=0
We multiply all the terms by the denominator
x*2x+9*2x+1=0
Wy multiply elements
2x^2+18x+1=0
a = 2; b = 18; c = +1;
Δ = b2-4ac
Δ = 182-4·2·1
Δ = 316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{316}=\sqrt{4*79}=\sqrt{4}*\sqrt{79}=2\sqrt{79}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{79}}{2*2}=\frac{-18-2\sqrt{79}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{79}}{2*2}=\frac{-18+2\sqrt{79}}{4} $
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