1/2x+x=200

Solution for 1/2x+x=200 equation:

1/2x+x=200

We move all terms to the left:

1/2x+x-(200)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

x+1/2x-200=0

We multiply all the terms by the denominator


x*2x-200*2x+1=0

Wy multiply elements

2x^2-400x+1=0

a = 2; b = -400; c = +1;
Δ = b2-4ac
Δ = -4002-4·2·1
Δ = 159992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{159992}=\sqrt{4*39998}=\sqrt{4}*\sqrt{39998}=2\sqrt{39998}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-400)-2\sqrt{39998}}{2*2}=\frac{400-2\sqrt{39998}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-400)+2\sqrt{39998}}{2*2}=\frac{400+2\sqrt{39998}}{4}
$