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1/2x+x=36
We move all terms to the left:
1/2x+x-(36)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
x+1/2x-36=0
We multiply all the terms by the denominator
x*2x-36*2x+1=0
Wy multiply elements
2x^2-72x+1=0
a = 2; b = -72; c = +1;
Δ = b2-4ac
Δ = -722-4·2·1
Δ = 5176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5176}=\sqrt{4*1294}=\sqrt{4}*\sqrt{1294}=2\sqrt{1294}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-2\sqrt{1294}}{2*2}=\frac{72-2\sqrt{1294}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+2\sqrt{1294}}{2*2}=\frac{72+2\sqrt{1294}}{4} $
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