1/2x-(x+1/5)=1/10(k+2)

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Solution for 1/2x-(x+1/5)=1/10(k+2) equation: 


x in (-oo:+oo)

(1/2)*x-x-(1/5) = (1/10)*(k+2) // - (1/10)*(k+2)

(1/2)*x-((1/10)*(k+2))-x-(1/5) = 0

(-1/10)*(k+2)+(1/2)*x-x-1/5 = 0

x/2-1/10*(k+2)-x-1/5 = 0

(-1/10*2*5*(k+2))/(2*5)+(5*x)/(2*5)+(2*5*(-x))/(2*5)+(-1*2)/(2*5) = 0

5*x-1/10*2*5*(k+2)+2*5*(-x)-1*2 = 0

5*x-k-10*x-2-2 = 0

-k-5*x-2-2 = 0

-k-5*x-4 = 0

(-k-5*x-4)/(2*5) = 0

(-k-5*x-4)/(2*5) = 0 // * 2*5

-k-5*x-4 = 0

-k-5*x-4 = 0 // + -k-4

-5*x = -(-k-4) // : -5

x = (-(-k-4))/(-5)

x = (k+4)/(-5)

x = (k+4)/(-5)

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