1/2x-(x-4)=2

Solution for 1/2x-(x-4)=2 equation:

1/2x-(x-4)=2

We move all terms to the left:

1/2x-(x-4)-(2)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We get rid of parentheses

1/2x-x+4-2=0

We multiply all the terms by the denominator


-x*2x+4*2x-2*2x+1=0

Wy multiply elements

-2x^2+8x-4x+1=0

We add all the numbers together, and all the variables

-2x^2+4x+1=0

a = -2; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·(-2)·1
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{6}}{2*-2}=\frac{-4-2\sqrt{6}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{6}}{2*-2}=\frac{-4+2\sqrt{6}}{-4}
$