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1/2x-11/4=2/3x
We move all terms to the left:
1/2x-11/4-(2/3x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/2x-(+2/3x)-11/4=0
We get rid of parentheses
1/2x-2/3x-11/4=0
We calculate fractions
(-198x^2)/96x^2+48x/96x^2+(-64x)/96x^2=0
We multiply all the terms by the denominator
(-198x^2)+48x+(-64x)=0
We get rid of parentheses
-198x^2+48x-64x=0
We add all the numbers together, and all the variables
-198x^2-16x=0
a = -198; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·(-198)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*-198}=\frac{0}{-396} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*-198}=\frac{32}{-396} =-8/99 $
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