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1/2x-1=12x+4
We move all terms to the left:
1/2x-1-(12x+4)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-12x-4-1=0
We multiply all the terms by the denominator
-12x*2x-4*2x-1*2x+1=0
Wy multiply elements
-24x^2-8x-2x+1=0
We add all the numbers together, and all the variables
-24x^2-10x+1=0
a = -24; b = -10; c = +1;
Δ = b2-4ac
Δ = -102-4·(-24)·1
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-14}{2*-24}=\frac{-4}{-48} =1/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+14}{2*-24}=\frac{24}{-48} =-1/2 $
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