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1/2x-2/3=1/4x-1
We move all terms to the left:
1/2x-2/3-(1/4x-1)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x-1)!=0We get rid of parentheses
x∈R
1/2x-1/4x+1-2/3=0
We calculate fractions
(-64x^2)/72x^2+36x/72x^2+(-18x)/72x^2+1=0
We multiply all the terms by the denominator
(-64x^2)+36x+(-18x)+1*72x^2=0
Wy multiply elements
(-64x^2)+72x^2+36x+(-18x)=0
We get rid of parentheses
-64x^2+72x^2+36x-18x=0
We add all the numbers together, and all the variables
8x^2+18x=0
a = 8; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·8·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*8}=\frac{-36}{16} =-2+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*8}=\frac{0}{16} =0 $
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