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1/2x-2/3x=3/4
We move all terms to the left:
1/2x-2/3x-(3/4)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/2x-2/3x-(+3/4)=0
We get rid of parentheses
1/2x-2/3x-3/4=0
We calculate fractions
(-54x^2)/96x^2+48x/96x^2+(-64x)/96x^2=0
We multiply all the terms by the denominator
(-54x^2)+48x+(-64x)=0
We get rid of parentheses
-54x^2+48x-64x=0
We add all the numbers together, and all the variables
-54x^2-16x=0
a = -54; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·(-54)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*-54}=\frac{0}{-108} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*-54}=\frac{32}{-108} =-8/27 $
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