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1/2x-24=3x-46
We move all terms to the left:
1/2x-24-(3x-46)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-3x+46-24=0
We multiply all the terms by the denominator
-3x*2x+46*2x-24*2x+1=0
Wy multiply elements
-6x^2+92x-48x+1=0
We add all the numbers together, and all the variables
-6x^2+44x+1=0
a = -6; b = 44; c = +1;
Δ = b2-4ac
Δ = 442-4·(-6)·1
Δ = 1960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1960}=\sqrt{196*10}=\sqrt{196}*\sqrt{10}=14\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-14\sqrt{10}}{2*-6}=\frac{-44-14\sqrt{10}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+14\sqrt{10}}{2*-6}=\frac{-44+14\sqrt{10}}{-12} $
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