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1/2x-2=28-4x
We move all terms to the left:
1/2x-2-(28-4x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(-4x+28)-2=0
We get rid of parentheses
1/2x+4x-28-2=0
We multiply all the terms by the denominator
4x*2x-28*2x-2*2x+1=0
Wy multiply elements
8x^2-56x-4x+1=0
We add all the numbers together, and all the variables
8x^2-60x+1=0
a = 8; b = -60; c = +1;
Δ = b2-4ac
Δ = -602-4·8·1
Δ = 3568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3568}=\sqrt{16*223}=\sqrt{16}*\sqrt{223}=4\sqrt{223}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{223}}{2*8}=\frac{60-4\sqrt{223}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{223}}{2*8}=\frac{60+4\sqrt{223}}{16} $
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