1/2x-2=4x-23

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Solution for 1/2x-2=4x-23 equation:



1/2x-2=4x-23
We move all terms to the left:
1/2x-2-(4x-23)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We get rid of parentheses
1/2x-4x+23-2=0
We multiply all the terms by the denominator
-4x*2x+23*2x-2*2x+1=0
Wy multiply elements
-8x^2+46x-4x+1=0
We add all the numbers together, and all the variables
-8x^2+42x+1=0
a = -8; b = 42; c = +1;
Δ = b2-4ac
Δ = 422-4·(-8)·1
Δ = 1796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1796}=\sqrt{4*449}=\sqrt{4}*\sqrt{449}=2\sqrt{449}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-2\sqrt{449}}{2*-8}=\frac{-42-2\sqrt{449}}{-16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+2\sqrt{449}}{2*-8}=\frac{-42+2\sqrt{449}}{-16} $

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