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1/2x-2=4x-23*
We move all terms to the left:
1/2x-2-(4x-23*)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(+4x)-2=0
We get rid of parentheses
1/2x-4x-2=0
We multiply all the terms by the denominator
-4x*2x-2*2x+1=0
Wy multiply elements
-8x^2-4x+1=0
a = -8; b = -4; c = +1;
Δ = b2-4ac
Δ = -42-4·(-8)·1
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{3}}{2*-8}=\frac{4-4\sqrt{3}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{3}}{2*-8}=\frac{4+4\sqrt{3}}{-16} $
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