1/2x-2x/3=6/x

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Solution for 1/2x-2x/3=6/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/2)*x-((2*x)/3) = 6/x // - 6/x

(1/2)*x-((2*x)/3)-(6/x) = 0

(1/2)*x+(-2/3)*x-6*x^-1 = 0

-1/6*x^1-6*x^-1 = 0

(-1/6*x^2-6*x^0)/(x^1) = 0 // * x^2

x^1*(-1/6*x^2-6*x^0) = 0

x^1

(-1/6)*x^2-6 = 0

(-1/6)*x^2-6 = 0

DELTA = 0^2-(-6*4*(-1/6))

DELTA = -4

DELTA < 0

x in { } 

x belongs to the empty set

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