1/2x-3(x)=-4

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Solution for 1/2x-3(x)=-4 equation:



1/2x-3(x)=-4
We move all terms to the left:
1/2x-3(x)-(-4)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We add all the numbers together, and all the variables
-3x+1/2x+4=0
We multiply all the terms by the denominator
-3x*2x+4*2x+1=0
Wy multiply elements
-6x^2+8x+1=0
a = -6; b = 8; c = +1;
Δ = b2-4ac
Δ = 82-4·(-6)·1
Δ = 88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{88}=\sqrt{4*22}=\sqrt{4}*\sqrt{22}=2\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{22}}{2*-6}=\frac{-8-2\sqrt{22}}{-12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{22}}{2*-6}=\frac{-8+2\sqrt{22}}{-12} $

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