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1/2x-3=2/x
We move all terms to the left:
1/2x-3-(2/x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/2x-(+2/x)-3=0
We get rid of parentheses
1/2x-2/x-3=0
We calculate fractions
x/2x^2+(-4x)/2x^2-3=0
We multiply all the terms by the denominator
x+(-4x)-3*2x^2=0
Wy multiply elements
-6x^2+x+(-4x)=0
We get rid of parentheses
-6x^2+x-4x=0
We add all the numbers together, and all the variables
-6x^2-3x=0
a = -6; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-6)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-6}=\frac{0}{-12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-6}=\frac{6}{-12} =-1/2 $
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