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1/2x-5x=100
We move all terms to the left:
1/2x-5x-(100)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-5x+1/2x-100=0
We multiply all the terms by the denominator
-5x*2x-100*2x+1=0
Wy multiply elements
-10x^2-200x+1=0
a = -10; b = -200; c = +1;
Δ = b2-4ac
Δ = -2002-4·(-10)·1
Δ = 40040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40040}=\sqrt{4*10010}=\sqrt{4}*\sqrt{10010}=2\sqrt{10010}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-2\sqrt{10010}}{2*-10}=\frac{200-2\sqrt{10010}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+2\sqrt{10010}}{2*-10}=\frac{200+2\sqrt{10010}}{-20} $
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