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1/2x-60=2+5x
We move all terms to the left:
1/2x-60-(2+5x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(5x+2)-60=0
We get rid of parentheses
1/2x-5x-2-60=0
We multiply all the terms by the denominator
-5x*2x-2*2x-60*2x+1=0
Wy multiply elements
-10x^2-4x-120x+1=0
We add all the numbers together, and all the variables
-10x^2-124x+1=0
a = -10; b = -124; c = +1;
Δ = b2-4ac
Δ = -1242-4·(-10)·1
Δ = 15416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15416}=\sqrt{4*3854}=\sqrt{4}*\sqrt{3854}=2\sqrt{3854}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-124)-2\sqrt{3854}}{2*-10}=\frac{124-2\sqrt{3854}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-124)+2\sqrt{3854}}{2*-10}=\frac{124+2\sqrt{3854}}{-20} $
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