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1/2x-7=1/(x-12)
We move all terms to the left:
1/2x-7-(1/(x-12))=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: (x-12))!=0We calculate fractions
x∈R
-22x^2)+(-(1*2x)/(-22x^2)+(1*(x-12)))/(-7=0
We add all the numbers together, and all the variables
-22x^2)+(-(+1*2x)/(-22x^2)+(1*(x-12)))/(-7=0
We calculate fractions
-22x^2)+(+(-(+1*2x)*()/((-22x^2)*()+(-22x^2)+(1*(x-12)))*()/((-22x^2)*()-7=0
We can not solve this equation
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