1/2x-7=1/3(x=12)

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Solution for 1/2x-7=1/3(x=12) equation: 



1/2x-7=1/3(x=12)

We move all terms to the left:

1/2x-7-(1/3(x)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 3x-7!=0

We move all terms containing x to the left, all other terms to the right

3x!=7

x!=7/3

x!=2+1/3

x∈R



We calculate fractions


(3x-7)/(6x^2-7)+(-(1*2x)/(6x^2-7)=0



We calculate terms in parentheses: +(-(1*2x)/(6x^2-7), so:

-(1*2x)/(6x^2-7

We add all the numbers together, and all the variables

-(+1*2x)/(6x^2-7

We multiply all the terms by the denominator


-(+1*2x)

We get rid of parentheses

-1*2x

Wy multiply elements

-2x

Back to the equation:

+(-2x)



We get rid of parentheses

(3x-7)/(6x^2-7)-2x=0

We multiply all the terms by the denominator


(3x-7)-2x*(6x^2-7)=0

We multiply parentheses

-12x^3+(3x-7)+14x=0

We get rid of parentheses

-12x^3+3x+14x-7=0

We do not support expression: x^3

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