1/2x-7=3(x-4)+3

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Solution for 1/2x-7=3(x-4)+3 equation: 



1/2x-7=3(x-4)+3

We move all terms to the left:

1/2x-7-(3(x-4)+3)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



We multiply all the terms by the denominator


-((3(x-4)+3))*2x-7*2x+1=0

Wy multiply elements

-((3(x-4)+3))*2x-14x+1=0

We add all the numbers together, and all the variables

-14x-((3(x-4)+3))*2x+1=0

We move all terms containing x to the left, all other terms to the right

-14x-((3(x-4)+3))*2x=-1

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